Prove the following limit.
lim (x -> 3) 3x - 7 = 2
SOLUTION 1. Preliminary analysis of the problem (guessing a value for δ). Let ε be a given positive number. We want to find a number δ such that
if 0 < |x - 3| < δ then |(3x - 7) - 2| < ε.
But |(3x - 7) - 2| = |3x - 9| = 3| |. Therefore, we want δ such that
if 0 < |x - 3| < δ then 3| | < ε
that is, if 0 < |x - 3| < δ then | | < ε/3.
This suggests that we should choose δ = ε/3.
2. Proof (showing that δ works). Given ε > 0, choose δ = ε/3. If
0 < | | < δ, then
|(3x - 7) - 2| = | |
= 3| | < 3δ
= 3( )
= ε.
Thus
if 0 < |x - 3| < δ then |(3x - 7) - 2| < ε.
Therefore, by the definition of a limit
lim (x -> 3) 3x - 7 = 2.