Exercise 5 a) Let A be a diagonalizable $n \times n$ matrix that has only $\lambda = 1$ and $\lambda = -1$ as eigenvalues. Show that $A^2$ is $I_n$, where $I_n$ is the $n \times n$ identity matrix. b) Let A be an $m \times n$ matrix, and let $K = A^tA$. Show that the identity $Nul(A) = Nul(K)$ holds for any choice of A.
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Step 1: Since A is diagonalizable, it can be written as A = PDP^-1, where D is a diagonal matrix with the eigenvalues of A on the diagonal and P is the matrix whose columns are the corresponding eigenvectors. Show more…
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