00:01
For this problem, we want to test the convergence of the following series.
00:04
Now the first one, we have summation from n equals 1 to infinity of 1 over n squared plus 1.
00:14
Now our nth term here for this series is a sub n which equals 1 over n squared plus 1.
00:23
And then we're going to compare this to another nth term of a series, let's say b sub n, which equals 1 over n squared.
00:35
Now 1 over n squared is greater than 1 over n squared plus 1.
00:42
And the series for this term, or for this nth term, 1 over n squared, is convergent by p series.
00:52
Test because p here equals 2 which is greater than 1.
01:00
And by that, by the direct comparison test, our series will converge as well.
01:07
Next we have the series summation from n equals 1 to infinity of n over 4n squared minus 3.
01:16
Now in here, a sub n is equal to n over 4n squared minus 3.
01:23
And we want to compare this to b sub n, which is equal to n over 4n squared, or that's 1 over 4n.
01:31
Now the series of bn, that is series of 1 over 4n equals 1 over 4 times the summation of 1 over n diverges since it's harmonic.
01:45
And we also find that n over 4n squared minus 3 is greater than n over 4n squared which equals 1 over 4n.
01:57
So by the direct comparison test, our series diverges...