Find an explicit solution of the given initial-value problem.\\ $x^2\frac{dy}{dx} = y - xy$, $y(-1) = -2$
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First, let's rewrite the given initial-value problem in the form of a first-order linear differential equation: 2dy/dx = y - xy^2 - 1 Rearranging the terms, we have: 2dy = (y - xy^2 - 1)dx Now, let's separate the variables by dividing both sides by (y - xy^2 - Show more…
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