Fill in the blanks in the partial decay series. Part A $^{226}_{89}Ac ightarrow ^{226}_{90}Th + ____$ Express your answer as a chemical expression.
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The problem states that it is 226 Ac, so A=226 and since Ac is Actinium, which is the 89th element on the periodic table, Z=89. The decay process releases a 4 2 He (Helium) atom. This means that the atomic mass (A) decreases by 4 and the atomic number (Z) Show more…
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Fill in the blanks in the partial decay series. Part A Express your answer as a chemical expression.
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