Find an equation of the line tangent to the curve defined by $x^4 + 5xy + y^2 = 40$ at the point $(2, 2)$. y =
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Taking the derivative of x^4 + 5xy + y^2 = 40 with respect to x, we get: 4x^3 + 5y + 5x(dy/dx) + 2y(dy/dx) = 0 Show more…
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