Question

Find equations of the tangent line and normal line to the given curve. $y = \frac{2x}{1 + 7x^2}$, $(1, \frac{1}{4})$ tangent line $y = \Box$ normal line $y = \Box$ SUBMIT ANSWER lock Browser Guard™ UV Search

Name: find equations of the tangent line and normal line to the given curve y frac2x1 7x2 1 frac14 tangent line y box normal line y box submit answer lock browser guardtm uv search 97807
Uploaded: 2020-10-16T14:47:37-08:00
Duration: 4 min 15 s
Channel: Jacquelyn Trost
Description: find equations of the tangent line and normal line to the given curve y frac2x1 7x2 1 frac14 tangent line y box normal line y box submit answer lock browser guardtm uv search 97807

          Find equations of the tangent line and normal line to the given curve.
$y = \frac{2x}{1 + 7x^2}$, $(1, \frac{1}{4})$
tangent line $y = \Box$
normal line $y = \Box$
SUBMIT ANSWER
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$find equations of the tangent line and normal line to the given curve y frac2x1 7x2 1 frac14 tangent line y box normal line y box submit answer lock browser guardtm uv search 97807$

Added by Gloria H.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Jacquelyn Trost

10/16/2020

Step 1

Step 1: Find the derivative of the function $y$ with respect to $x$, which represents the slope of the tangent line. We use the quotient rule for differentiation: If $y = \frac{u}{v}$, then $\frac{dy}{dx} = \frac{u'v - uv'}{v^2}$. Here, $u = 2x$ and $v = 1 + Show more…

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Find equations of the tangent line and normal line to the given curve. $y = \frac{2x}{1 + 7x^2}$, $(1, \frac{1}{4})$ tangent line $y = \Box$ normal line $y = \Box$ SUBMIT ANSWER lock Browser Guard™ UV Search