Find $f$. $f''(x) = 8 + 6x + 36x^2, quad f(0) = 3, quad f(1) = 15$ $f(x) =$
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Step 1: Find the first derivative of f(x) using f"(x) = 8 + 6x + 36x^2 Given f"(x) = 8 + 6x + 36x^2, integrate to find f'(x): f'(x) = ∫(8 + 6x + 36x^2) dx f'(x) = 8x + 3x^2 + 12x^3 + C1, where C1 is the constant of integration Show more…
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