Find the absolute extrema of the function on the closed interval. Use a graphing utility to verify your results. (If an answer does not exist, enter DNE.) f(x) = x^2 - 6x - 6, [0, 3] absolute maximum (x, y) = absolute minimum (x, y) =
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\[f'(x) = 2x - 6\] \[2x - 6 = 0\] \[2x = 6\] \[x = 3\] ** Show more…
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