Find the absolute extrema of the function on the closed interval. f(x) = 6 - x, [-2, 3] minimum (x, y) = ( maximum (x, y) = (
Added by Haley K.
Close
Step 1
**Step 2:** Since there are no critical points, the absolute extrema will occur at the boundary points of the interval \([-2, 3]\). **Step 3:** Evaluate the function at the boundary points: Show more…
Show all steps
Your feedback will help us improve your experience
Avinash Vishwakarma and 67 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Find the absolute extrema of the function on the closed interval. $$f(x)=2 x^{3}-6 x,[0,3]$$
Applications of Differentiation
Extrema on an Interval
Find the absolute extrema of the function on the closed interval. Use a graphing utility to verify your results. (If an answer does not exist, enter DNE.) f(x) = x^2 - 6x - 6, [0, 3] absolute maximum (x, y) = absolute minimum (x, y) =
Suman Saurav T.
Find the relative extrema of each function, if they exist. List each extremum along with the $x$ -value at which it occurs. Then sketch a graph of the function. $$f(x)=x^{2}+6 x-3$$
Using First Derivatives to Find Maximum and Minimum Values and Sketch Graphs
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD