Find the angle ( heta ) between the vectors. [ egin{aligned} vec{u} &=langle 3,-3 angle \ vec{v} &=langle-2,2 sqrt{3} angle end{aligned} ]
Added by Peter R.
Close
Step 1
Step 1: Find the magnitude of vector A (U): The magnitude of vector A (U) is given by ||U|| = √(3^2 + (-3)^2) = √(9 + 9) = √18 = 3√2. Show more…
Show all steps
Your feedback will help us improve your experience
Vishal Parmar and 56 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Find the angle $\theta$ between the vectors. $$\begin{aligned} &\mathbf{u}=2 \mathbf{i}\\ &\mathbf{v}=-3 \mathbf{j} \end{aligned}$$
Additional Topics in Trigonometry
Vectors and Dot Products
Find the angle $\theta$ between the vectors. $$ \begin{aligned} &\mathbf{u}=3 \mathbf{i}+2 \mathbf{j}+\mathbf{k} \\ &\mathbf{v}=2 \mathbf{i}-3 \mathbf{j} \end{aligned} $$
Vectors and the Geometry of Space
The Dot Product of Two Vectors
Find the angle $\theta$ between the given vectors. $$ \mathbf{a}=3 \mathbf{i}-\mathbf{k}, \mathbf{b}=2 \mathbf{i}+2 \mathbf{k} $$
Vectors and 3-Space
Dot Product
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD