Find the area of the surface generated when the given curve is revolved about the given axis. y = 22x + 66, for 0 ≤ x ≤ 4; about the x-axis Question content area bottom Part 1 The surface area is [enter your response here] square units
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This can be done using the formula for arc length: \[ L = \int_{a}^{b} \sqrt{1 + \left(\frac{dy}{dx}\right)^2} dx \] Given that \( y = 22x + 66 \), we can find \( \frac{dy}{dx} \) by taking the derivative of y with respect to x: \[ \frac{dy}{dx} = 22 \] Show more…
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