Find the critical numbers of the function. (Enter your answers as a comma-separated list.) s(t) = 3t^4 + 20t^3 - 18t^2 t =
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s'(t) = 12t^3 - 60t^2 + 36t Now, we need to find the critical numbers by setting the derivative equal to zero and solving for t. 12t^3 - 60t^2 + 36t = 0 We can factor out a common factor of 12t: 12t(t^2 - 5t + 3) = 0 Now, we need to solve the quadratic Show more…
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