Find the direction cosines and direction angles of the vector. (Give the direction angles correct to the nearest tenth of a degree.) (2, 1, 3) cos($$\alpha$$) = cos($$\beta$$) = cos($$\gamma$$) = $$\alpha$$ = $$\beta$$ = $$\gamma$$ =
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The magnitude of the vector is $$||\vec{v}|| = \sqrt{2^2 + 1^2 + 3^2} = \sqrt{4 + 1 + 9} = \sqrt{14}$$. Show more…
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