Find the equation of the tangent line to the curve $4x^2 + 3y^2 - 13 = 2xy - x$ at the point $(1, 2)$. a) $2y - x = 5$ b) $x + 2y = 5$ c) $2x - y = 0$ d) $x + 2y = 3$ e) $-2x - y = -4$
Added by Javier W.
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We can do this by using the Pythagorean theorem: 4x2 + 3y2 = 13 We can then use the slope equation to find the equation of the tangent line: y = -(x + 2) / (13 + x) Since y = -(x + 2) / (13 + x), we can write the equation of the tangent line as: y = -8x + Show more…
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