Question

Find the equation of the tangent line to the curve y = (x - 1)^9 (x + 2)^2 at the point (2, 16). The equation of the tangent line to the curve at the given point is y = . (Type an expression using x as the variable.)

Name: Find the equation of the tangent line to the curve y = (x - 1)^9 (x + 2)^2 at the point (2, 16). The equation of the tangent line to the curve at the given point is y = . (Type an expression using x as the variable.)
Uploaded: 2023-02-26T00:30:58-08:00
Duration: 3 min 5 s
Channel: Zhumagali Shomanov
Description: Find the equation of the tangent line to the curve y = (x - 1)^9 (x + 2)^2 at the point (2, 16). The equation of the tangent line to the curve at the given point is y = . (Type an expression using x as the variable.)

          Find the equation of the tangent line to the curve y = (x - 1)^9 (x + 2)^2 at the point (2, 16). The equation of the tangent line to the curve at the given point is y = . (Type an expression using x as the variable.)

Find the equation of the tangent line to the curve y = (x - 1)^9 (x + 2)^2 at the point (2, 16). The equation of the tangent line to the curve at the given point is y = . (Type an expression using x as the variable.)

Added by Holly T.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Zhumagali Shomanov

02/26/2023

Step 1

First, we need to find the derivative of the curve y = (x-1+2)^2 using the chain rule: y' = 2(x-1+2)(1) = 2(x+1) Show more…

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Find the equation of the tangent line to the curve y = (x - 1)^9 (x + 2)^2 at the point (2, 16). The equation of the tangent line to the curve at the given point is y = . (Type an expression using x as the variable.)