Question

Find the indefinite integral of the following function.\\ $\int \frac{\sin t}{\cos^2 t} dt$\\ a) $\frac{(\sin t)^2}{3} + C$\\ b) $\frac{(\cos t)^2}{3} + C$\\ c) $\frac{(\cos t)^2}{2} + C$\\ d) $\frac{(\cos t)^3}{2} + C$\\ e) $\frac{(\sin t)^3}{2} + C$

          Find the indefinite integral of the following function.\\
$\int \frac{\sin t}{\cos^2 t} dt$\\
a) $\frac{(\sin t)^2}{3} + C$\\
b) $\frac{(\cos t)^2}{3} + C$\\
c) $\frac{(\cos t)^2}{2} + C$\\
d) $\frac{(\cos t)^3}{2} + C$\\
e) $\frac{(\sin t)^3}{2} + C$

Find the indefinite integral of the following function.

∫(sin t)/(cos^2 t) dt

a) ((sin t)^2)/(3) + C

b) ((cos t)^2)/(3) + C

c) ((cos t)^2)/(2) + C

d) ((cos t)^3)/(2) + C

e) ((sin t)^3)/(2) + C

Added by Kyle B.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Zhumagali Shomanov

06/19/2023

Step 1

Let u = cos(t), then du = -sin(t) dt. Show more…

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