Question

Find the inverse Laplace transform of \begin{equation} F(s) = \frac{e^{-6s}}{s^2 + 1s - 12} \end{equation} \begin{equation} f(t) = (t - 6) \left(\frac{1}{7}e^{3(t-6)} - \frac{1}{7}e^{-4(t-6)}\right) \text{ (Use step(t-a) for } u_a(t) ) \end{equation}

          Find the inverse Laplace transform of
\begin{equation} 
F(s) = \frac{e^{-6s}}{s^2 + 1s - 12}
\end{equation}
\begin{equation} 
f(t) = (t - 6) \left(\frac{1}{7}e^{3(t-6)} - \frac{1}{7}e^{-4(t-6)}\right) \text{ (Use step(t-a) for } u_a(t) )
\end{equation}

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Find the inverse Laplace transform of

F(s) = (e^-6s)/(s^2 + 1s - 12)

f(t) = (t - 6) ((1)/(7)e^3(t-6) - (1)/(7)e^-4(t-6)) (Use step(t-a) for ua(t) )

Added by Anthony B.

Calculus: Early Transcendentals

James Stewart 8th Edition

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