Find the limit: $\lim_{x\to 1} \frac{x^2 - x + 3}{x - 1} =$ $\lim_{x\to 1} \frac{x^2 - x + 3}{x - 1}$
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First, let's try to substitute $x=1$ into the function to see if we get a determinate form. Numerator: $1^2 - 1 + 3 = 1 - 1 + 3 = 3$ Denominator: $1 - 1 = 0$ Since the numerator approaches a non-zero number (3) and the denominator approaches 0, the limit will be Show more…
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