Question

Find the limit of $f(t) = \frac{7 - 4t + \sin 3t}{6t + \cos 3t}$ as $t$ approaches $-\infty$. $\lim_{t \to -\infty} f(t) = $ (Simplify your answer.)

          Find the limit of $f(t) = \frac{7 - 4t + \sin 3t}{6t + \cos 3t}$ as $t$ approaches $-\infty$.
$\lim_{t \to -\infty} f(t) = $ (Simplify your answer.)

Find the limit of f(t) = (7 - 4t + sin 3t)/(6t + cos 3t) as t approaches -∞.
limt → -∞ f(t) = (Simplify your answer.)

Added by Autumn R.

Calculus: Early Transcendentals

James Stewart 8th Edition

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Find the limit of f(t)=(7-4t+sin3t)/(6t+cos3t) as t approaches -infty . lim_(t->-infty )f(t)= (Simplify your answer.) 7 - 4t + sin 3t Find the limit of f(t) = as t approaches - . 6t+ cos 3t lim f(t) t-8 (Simplify your answer.