Find the linearization to $f(x) = 3^{(2x^2+1)}$ at $x = 1$, and use it to approximate $f(0.95)$.
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To find the linearization of f(x) at x=1, we need to find the first derivative of f(x) and evaluate it at x=1. Given f(x) = 3^(2x^2 + 1), we first find the derivative of f(x) using the chain rule: f'(x) = ln(3) * 3^(2x^2 + 1) * 4x Now, we evaluate f'(1): f'(1) Show more…
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