Question

Find the parametric equations of the plane that contains the following two parallel lines: $L_1: (x, y, z) = (2, 4, 1) + t(3, -1, 1)$ and $L_2: (x, y, z) = (1, 4, 4) + t(-6, 2, -2)$ Q2: (T=3, C=1) Determine the Cartesian equation of the plane that a. contains the point $P(-2, 6, 1)$ and has normal vector $(2, -4, 5)$ b. contains the point $P(-2, 0, 6)$ and the line $\frac{x - 4}{3} = \frac{y + 2}{-5} = \frac{z - 1}{2}$

          Find the parametric equations of the plane that contains the following two parallel
lines:
$L_1: (x, y, z) = (2, 4, 1) + t(3, -1, 1)$ and
$L_2: (x, y, z) = (1, 4, 4) + t(-6, 2, -2)$
Q2: (T=3, C=1)
Determine the Cartesian equation of the plane that
a. contains the point $P(-2, 6, 1)$ and has normal vector $(2, -4, 5)$
b. contains the point $P(-2, 0, 6)$ and the line $\frac{x - 4}{3} = \frac{y + 2}{-5} = \frac{z - 1}{2}$

Find the parametric equations of the plane that contains the following two parallel
lines:
L1: (x, y, z) = (2, 4, 1) + t(3, -1, 1) and
L2: (x, y, z) = (1, 4, 4) + t(-6, 2, -2)
Q2: (T=3, C=1)
Determine the Cartesian equation of the plane that
a. contains the point P(-2, 6, 1) and has normal vector (2, -4, 5)
b. contains the point P(-2, 0, 6) and the line (x - 4)/(3) = (y + 2)/(-5) = (z - 1)/(2)

Added by Mark W.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Zhumagali Shomanov

10/26/2022

Step 1

The direction vector of the first line L1 is d1 = <1, 1, 3>. The direction vector of the second line L2 is d2 = <4, -6, -2>. Show more…

Show all steps

Thanks for your feedback!

Find the parametric equations of the plane that contains the following two parallel Lx.y.=2,4,1+3.1,1and Lx.y.=1.4.4+-6.2.-2 lines: Q2:T=3,C=1 Determine the Cartesian cquation of the plane that a.contains the point P(-2,6,1 and has normal vector 2,-4.5 b.contains the point P2.0.6and the line