Question

Find the partial fraction decomposition. (x - 5) / (x^2 - 64) A. (13/16) / (x + 8) + (3/16) / (x - 8) B. -(13/16) / (x + 8) + (3/16) / (x - 8) C. 13 / (x + 16) + 3 / (x - 16) D. (13/16) / (x - 8) + (3/16) / (x + 8)

Name: Find the partial fraction decomposition. (x - 5) / (x^2 - 64) A. (13/16) / (x + 8) + (3/16) / (x - 8) B. -(13/16) / (x + 8) + (3/16) / (x - 8) C. 13 / (x + 16) + 3 / (x - 16) D. (13/16) / (x - 8) + (3/16) / (x + 8)
Uploaded: 2023-06-20T22:48:15-08:00
Duration: 2 min 37 s
Channel: Adi S
Description: Find the partial fraction decomposition. (x - 5) / (x^2 - 64) A. (13/16) / (x + 8) + (3/16) / (x - 8) B. -(13/16) / (x + 8) + (3/16) / (x - 8) C. 13 / (x + 16) + 3 / (x - 16) D. (13/16) / (x - 8) + (3/16) / (x + 8)

          Find the partial fraction decomposition. (x - 5) / (x^2 - 64) A. (13/16) / (x + 8) + (3/16) / (x - 8) B. -(13/16) / (x + 8) + (3/16) / (x - 8) C. 13 / (x + 16) + 3 / (x - 16) D. (13/16) / (x - 8) + (3/16) / (x + 8)

$Find the partial fraction decomposition. (x - 5) / (x^2 - 64) A. (13/16) / (x + 8) + (3/16) / (x - 8) B. -(13/16) / (x + 8) + (3/16) / (x - 8) C. 13 / (x + 16) + 3 / (x - 16) D. (13/16) / (x - 8) + (3/16) / (x + 8)$

Added by Jacob H.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Adi S

06/20/2023

Step 1

First, we need to factor the denominator: x^2 - 64 = (x+8)(x-8) So, we can write the fraction as: (X-5) / (x+8)(x-8) + 13/(x+8) + 3/(x-8) + 16/(x^2-64) Show more…

Show all steps

Thanks for your feedback!

Find the partial fraction decomposition. x-5 / (x^2 - 64) A. (13/16)/(x+8) + (3/16)/(x-8) B. -(13/16)/(x+8) + (3/16)/(x-8) C. 13/(x+16) + 3/(x-16) D. (13/16)/(x-8) + (3/16)/(x+8)