00:01
In this question, we are asked to find the slope of the tangent line at x equals 6.
00:05
This means we need to calculate y ' of 6.
00:10
First we need to find y ' of x.
00:13
To do that, we need to differentiate 3 times 7 plus x to the negative first power.
00:21
And this equals negative 3 multiplied by 7 plus x to the negative second power.
00:29
Or negative 3 divided by 7 plus x squared.
00:34
Now we need to plug in x equals 6.
00:38
We'll get negative 3 divided by 7 plus 6 squared.
00:44
That's negative 3 divided by 13 squared.
00:48
And equals negative 3 divided by 169.
00:52
This is the slope in this question.
00:57
Let's move on to the next question...