Find the sum of the convergent series. [ sum_{n=1}^{infty} frac{24}{n(n+2)} ]
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We start by expressing \(\frac{24}{n(n+2)}\) as a sum of simpler fractions: \[ \frac{24}{n(n+2)} = \frac{A}{n} + \frac{B}{n+2} \] Show more…
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