Question

Find the unit tangent vector of the given curve.\\ r(t) = (8 \sin^3 10t)i + (8 \cos^3 10t)j\\ A. T = (8 \sin 10t)i - (8 \cos 10t)j\\ B. T = (8 \cos 10t)i - (8 \sin 10t)j\\ C. T = (\sin 10t)i - (\cos 10t)j\\ D. T = (240 \sin 10t)i - (240 \cos 10t)j

          Find the unit tangent vector of the given curve.\\
r(t) = (8 \sin^3 10t)i + (8 \cos^3 10t)j\\
A. T = (8 \sin 10t)i - (8 \cos 10t)j\\
B. T = (8 \cos 10t)i - (8 \sin 10t)j\\
C. T = (\sin 10t)i - (\cos 10t)j\\
D. T = (240 \sin 10t)i - (240 \cos 10t)j

Find the unit tangent vector of the given curve.

r(t) = (8 sin^3 10t)i + (8 cos^3 10t)j

A. T = (8 sin10t)i - (8 cos10t)j

B. T = (8 cos10t)i - (8 sin10t)j

C. T = (sin10t)i - (cos10t)j

D. T = (240 sin10t)i - (240 cos10t)j

Added by Amy B.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Tahleem K

02/24/2022

Step 1

r'(t) = (240 sin² 10t cos 10t)i - (240 cos² 10t sin 10t)j Show more…

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Find the unit tangent vector of the given curve. r(t) = (8 sin³ 10t)i + (8 cos³ 10t)j A. T= (8 sin 10t)i - (8 cos 10t)j B. T = (8 cos 10t)i - (8 sin 10t)j C. T = (sin 10t)i - (cos 10t)j D. T (240 sin 10t)i - (240 cos 10t)j