00:01
For this problem, we are asked to find the values of a and b that make the given function continuous everywhere.
00:06
So we can see we have two unknowns a and b, and for the function to be continuous everywhere, we first need to have that the given functions are continuous, or that the given pieces are continuous everywhere, and essentially we need to solve so that everything matches up.
00:20
So first, we'll take the limit as x approaches 2 of f of x, so that's the limit of x approaches 2 of x squared minus 4.
00:30
Divided by x minus 2, which would be equal to the limit as x approaches 2 of, well, we can factor this with difference of squares.
00:41
That would be x minus 2 times x plus 2 over x minus 2.
00:47
So we can see that the x minus 2 is divide out, and we get a value of 4.
00:51
So that means that we need to have that the limit as x approaches 2 of a x squared minus bx plus 3, must be equal to 4.
01:06
So, well, we'll leave that aside for now.
01:09
Actually, we don't really need to leave that too far aside for now.
01:13
This would just be equal to 4a minus 2b plus 3 must be equal to 4.
01:22
Or 4a minus 2b equals 1...