Question

Find the volume of the parallelepiped determined by the vectors \vec{a} = \langle 5, 4, -1 \rangle, \vec{b} = \langle 0, 1, 2 \rangle, \vec{c} = \langle 2, 4, 1 \rangle. Volume = cubic-units

          Find the volume of the parallelepiped determined by the vectors \vec{a} = \langle 5, 4, -1 \rangle, \vec{b} = \langle 0, 1, 2 \rangle, \vec{c} = \langle 2, 4, 1 \rangle.
Volume =  cubic-units

Find the volume of the parallelepiped determined by the vectors a⃗ = ⟨5, 4, -1 ⟩, b⃗ = ⟨0, 1, 2 ⟩, c⃗ = ⟨2, 4, 1 ⟩.
Volume = cubic-units

Added by Jason T.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Adi S

04/07/2023

Step 1

The scalar triple product of three vectors a, b, and c is given by the determinant of the matrix formed by the three vectors: V = |a ⋅ (b × c)| Show more…

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Find the volume of the parallelepiped determined by the vectors vec(a)=(:5,4,-1:), vec(b)=(:0,1,2:),vec(c)=(:2,4,1:). Volume = cubic-units Question Help: Video Find the volume of the parallelepiped determined by the vectors a = (5, 4, -- 1) b=(0,1,2,c=(2,4,1) Volume= cubic-units Question Help:Video Submit Question