Question

Find where the first derivative is equal to 0. Use this value and the point to find the equation of the tangent line.\\ $y = -\frac{1}{4}x + 3$, $y = \frac{1}{4}x$

          Find where the first derivative is equal to 0. Use this value and the point to find the equation of the tangent line.\\
$y = -\frac{1}{4}x + 3$, $y = \frac{1}{4}x$

Find where the first derivative is equal to 0. Use this value and the point to find the equation of the tangent line.

y = -(1)/(4)x + 3, y = (1)/(4)x

Added by Julia H.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Zhumagali Shomanov

04/04/2023

Step 1

To find where the first derivative is equal to 0, we need to find the critical points of the function. The first derivative of y = -(1/4)x + 3 is -1/4. Setting this equal to 0, we get: -1/4 = 0 This equation has no solution, which means that the first derivative Show more…

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Find where the first derivative is equal to 0 . Use this value and the point to find the equation of the tangent line. y=-(1)/(4)x+3,y=(1)/(4)x Find where the first derivative is equal to 0 . Use this value and the point to find the equation of the tangent line y=-4x+3,y=1x