For $f(x) = 2x^4 - 4x^2 + 6$ find the following. (A) $f'(x)$ (B) The slope of the graph of f at $x = -3$ (C) The equation of the tangent line at $x = -3$ (D) The value(s) of x where the tangent line is horizontal (A) $f'(x) = $
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To find the derivative of f(x), we need to differentiate each term separately. The derivative of 2x^4 is 8x^3 (using the power rule). The derivative of -42 is 0 (since it is a constant). The derivative of 6 is 0 (since it is a constant). So, the derivative of Show more…
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