00:01
We are given with few functions and we need to find if the functions have the removable discontinuity at the given values of a.
00:11
And if s, we need to find the value of g of a where g of a agrees with f of x for x not equal to a.
00:22
In the first part, we are given with f of x is equal to x square minus 2x minus 8 divided by x plus.
00:31
2 and the value of a is equal to minus 2.
00:34
If we substitute x is equal to minus 2 in the denominator, the function will be undefined.
00:39
So let's compute the limit of f of x when x tends to minus 2.
00:46
It is equal to the limit when x tends to minus 2, the derivative of what is in the numerator and the derivative of what is in the denominator.
00:57
If we differentiate numerator, we will get 2x minus 2.
01:02
Differentiate the denominator, we will get 1.
01:05
So it will be equal to 2 times minus 2, which is equal to minus 6.
01:11
So what we can say is the value of g of a in this case is nothing but minus 6.
01:19
The function f of x has removable discontinuity at a is equal to minus 2.
01:25
Now let's move on to the part 2.
01:27
In part 2, we have f of x is equal to x minus 7 divided by modulus of x minus 7 we know that modulus of x minus 7 is not differentiable at x is equal to 7 why because the left -hand limit of f of x will be equal to minus 1 where the right -hand limit will be equal to 1 as both of them are not equal the function doesn't have removable discontinuity at x is equal to 7.
02:10
So this is the answer for the second part of the problem.
02:14
In the third part, we have f of x is equal to x cube plus 64 divided by x plus 4.
02:23
If we substitute x is equal to minus 4 in the denominator, it will be equal to 0...