00:01
Hello, so for part a to find the magnitude and direction, well, the magnitude of the cross product, the magnitude of the cross product, a vector crossed with b vector, is going to be equal to the magnitude of a times the magnitude of b times sine of the angle.
00:22
Theta here.
00:24
So here, theta is the angle between the two vectors, and we have that theta, seems to be 60 plus 60.
00:30
So in this case, theta is going to be 120 degrees.
00:34
And we put in the known values, and we get that the magnitude of the cross product is going to be 2 .8 centimeters times 1 .90 centimeters and then times sign of 120 degrees.
00:50
Sign of 120 is equal to sign of 60, which is root 3 over 2.
00:54
So this is going to be 2 .8 times 1 .9 times square root of 3 over 2.
01:03
That's going to be approximately 4 .76 times 0 .86, which is going to be approximately 4 .12 centimeters squared...
