00:01
High students in this question, a four capacitor substitute has been given with the value of capacitance c1 to be equal to 15 micro -farrad, the capacitance c2 is taken as 3 micro -farrad, the capacitance 3 is taken as 6 micro -farrants, and finally the capacitance 4 is taken to be 20 micro -farrants.
00:22
Now in the first part of the question, we are asked to find out the equivalent capacitance which is taken as ce.
00:27
And in this question it is given that the voltage across point a and b is taken as vap which is equal to 15 volt.
00:37
Now from this figure we can say that the value of c1 is in series with c2, therefore the total capacitance can be taken as c12 to be equal to c1 into c2 divided by c1 plus c2.
00:50
Now by substituting the values and undergoing simplification, we get the value of c12 to be equal to 2 .5.
00:57
Micro -parret.
00:59
Next we can say that the value of c -1 -2 is in parallel arrangement with c -3, therefore in that case the total capacitance can be taken as c -123 which is equal to the sum of c -1 -2 plus c -3.
01:14
Now by substituting the values and undergoing simplification, we get the value of c -1 -2 -3 to be equal to 8 .5 micro -farrad.
01:23
Next we can consider capacitance c -1 -2 -3 as well as c4.
01:28
Which are in series arrangement.
01:30
Therefore for that particular case, the total capacitance c1234 will be equal to the product of c123 into c4 divided by sum of c123 plus c4.
01:43
Now by substituting the values and undergoing simplification, we get the value of capacitance 123 to be equal to 5 .965 microval.
01:53
Now the equivalent resistance can be taken as c .e which is equal to the value of c1234 that is equal to 5 .965 micro phall.
02:04
Now in the second part of the question, we are asked to find out the charge associated with each capacitor...