What is the equation for the tangent line to the graph of the function $f(x) = x - 2x^2$ at the given point $(1, -1)$? a. $y = 1 - 4x$ b. $y + 1 = -3(x - 1)$ c. $y - 1 = (x - 1)$ d. $y = x - 2x$ e. $y + 1 = 4(x - 1)$
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To find the equation of the tangent line, we need to find the derivative of the function f(x). The given function is f(x) = x^2x. Using the power rule, we can find the derivative as follows: f'(x) = 2x * x^2 + x^2 * 1 = 2x^3 + x^2 Show more…
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