Given 100.0 mL of a buffer that is 0.50 M in HOCl and 0.61 M in NaOCl, what is the pH after 10.0 mL of 1.0 M NaOH has been added? (Ka for HOCl = 3.5 x 10^(-8)) 7.56 7.64 7.46 7.21 7.71
Added by Josep H.
Step 1
Calculate the moles of HOCl and NaOCl in the buffer before adding NaOH. Moles of HOCl = 0.50 M * 0.100 L = 0.050 mol Moles of NaOCl = 0.61 M * 0.100 L = 0.061 mol Show more…
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