00:01
Hi, in this question we have to calculate the ph of this buffer solution after adding n -a -o -h solution.
00:08
Now first we have to calculate the moles of h -o -c -l.
00:13
So now using this equation here we can calculate the moles as molarity multiply by volume in ml divided by 1000.
00:27
Now here we are dividing it by 1000 because we are converting volume which is given in ml into liters.
00:34
So let n represent the moles.
00:37
So moles of hocl is equal to molarity that is 0 .50 molar.
00:43
Multiply by volume is 100.
00:45
So we write liter here because we have converted it into liters.
00:50
So divided by 1 ,000.
00:52
Now 1 molar is equal to 1 mole per liter.
00:57
So these are both same things.
01:00
So from here, moles of hocl.
01:03
Are 0 .05 mole.
01:07
Now similarly we can calculate the moles of n -a -o -h that is as equal to 0 .1 .0 molar multiply by 10 liter here and 1 ,000 divided by 1000.
01:22
So this is as equal to 0 .01 mole.
01:26
Now h -o -c -l react with n -a -o -h as it gives n -a -o -c -l plus h2.
01:36
Now here 1 mole of hocl are getting neutralized by 1 mole of naoh...