Question

Given that R(x) = (96) / ((6x - 10)^(2)) and x_(0) = (17) / (3), find R'(x) = R'(x_(0)) = The equation of the line tangent to the curve at x = x_(0) is Note: Type answer in form y = mx + b. Note: You can earn partial credit on this problem.

Name: given that rx 96 6x 102 and x0 17 3 find rx rx0 the equation of the line tangent to the curve at x x0 is note type answer in form y mx b note you can earn partial credit on this problem 68768
Uploaded: 2022-05-06T20:05:06-08:00
Duration: 4 min 36 s
Channel: Ahmet Yavas
Description: given that rx 96 6x 102 and x0 17 3 find rx rx0 the equation of the line tangent to the curve at x x0 is note type answer in form y mx b note you can earn partial credit on this problem 68768

          Given that R(x) = (96) / ((6x - 10)^(2)) and x_(0) = (17) / (3), find
R'(x) =
R'(x_(0)) =
The equation of the line tangent to the curve at x = x_(0) is
Note: Type answer in form y = mx + b.
Note: You can earn partial credit on this problem.

given that rx 96 6x 102 and x0 17 3 find rx rx0 the equation of the line tangent to the curve at x x0 is note type answer in form y mx b note you can earn partial credit on this problem 68768

Added by Thomas C.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Ahmet Yavas

05/06/2022

Step 1

R'(x) = -2 * (96) / ((6x - 10)^(3)) * 6 R'(x) = -1152 / ((6x - 10)^(3)) Show more…

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Given that R(x) = (96) / ((6x - 10)^(2)) and x_(0) = (17) / (3), find R'(x) = R'(x_(0)) = The equation of the line tangent to the curve at x = x_(0) is Note: Type answer in form y = mx + b. Note: You can earn partial credit on this problem.