Given: The mechanism shown below is made up of links AB, BE and CE. Links AB and CE are pinned to ground at pins A and C, respectively. Link BE is pinned to links AB and CE at pins B and E, respectively. Link AB is rotating CCW at a constant rate of $omega_{AB}$. In the position shown link AB is horizontal, and link CE is vertical. Find: For this position, determine the angular velocity for links BE and CE. $omega_{AB}$ r A B L E d C Use the following parameters in your analysis: r = 0.2 ft, L = 0.5 ft, d = 0.4 ft and $omega_{AB}$ = 4 rad/s.
Added by Jacob J.
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We can use the equation: wBE = wAB + wAE where wAB is the angular velocity of link AB and wAE is the angular velocity of link AE. Since link AB is rotating at a constant rate of 4 rad/s, we have: wAB = 4 rad/s Show more…
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