Given the two vectors: vec{A}=(3 hat{i}-2 hat{j}) and vec{B}=(4 hat{i}-4 hat{j}) The smallest angle enclosed (????????) between them is close to: A. 35.5Âș B. 63.5Âș C. 74.5Âș D. 98.5Âș E. 11.3Âș
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The dot product of two vectors is given by the formula: \(\vec{A} \cdot \vec{B} = |\vec{A}| |\vec{B}| \cos(\theta)\) where \(|\vec{A}|\) and \(|\vec{B}|\) are the magnitudes of the vectors and \(\theta\) is the angle between them. The dot product of Show moreâŠ
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