Question

Given the vector vec{u} = 2vec{i} + -5vec{j}, find the magnitude and angle in which the vector points (measured in radians counterclockwise from the positive x-axis and 0 le heta < 2pi). Round each decimal to two places. ||vec{u}|| = 5.39 heta = 5.09

          Given the vector vec{u} = 2vec{i} + -5vec{j}, find the magnitude and angle in which the vector points (measured in radians counterclockwise from the positive x-axis and 0 le 	heta < 2pi). Round each decimal to two places.
||vec{u}|| = 5.39
	heta = 5.09

Given the vector vecu = 2veci + -5vecj, find the magnitude and angle in which the vector points (measured in radians counterclockwise from the positive x-axis and 0 le heta < 2pi). Round each decimal to two places.
||vecu|| = 5.39
heta = 5.09

Added by Jillian C.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Andrew Noble

04/11/2023

Step 1

The magnitude of a vector u = ai + bj is given by ||u|| = √(a^2 + b^2). In this case, a = 2 and b = 5, so ||u|| = √(2^2 + 5^2) = √(4 + 25) = √29. Now, we find the angle θ. We can use the tangent function to find the angle: tan(θ) = b/a. So, θ = arctan(b/a) = Show more…

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Given the vector u = 2i + 5j, find the magnitude and angle in which the vector points (measured in radians counterclockwise from the positive x-axis and 0 < θ < 2π). Round each decimal to two places. Magnitude: 5.3851 Angle: 201.8014