Given the vector $vec{u} = -4vec{i} + -6vec{j}$, find the magnitude and angle in which the vector points (measured in radians counterclockwise from the positive x-axis and $0 le heta < 2pi$). Round each decimal to two places.
Added by Christopher T.
Step 1
Substituting the values given in the problem, we get: |→u| = √((-4)^2 + (-6)^2) = √(16 + 36) = √52 Rounding to two decimal places, we get: |→u| ≈ 7.21 Therefore, the magnitude of the vector →u is approximately 7.21. Show more…
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