Consider the function $f(x) = 2x^3 + 24x^2 - 120x + 11$, $-10 \le x \le 3$. This function has an absolute minimum value equal to and an absolute maximum value equal to
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f'(z) = 2z^2 + 4z + 120 Setting f'(z) = 0, we get: 2z^2 + 4z + 120 = 0 Show more…
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