Question

How many atoms are present in $123 \mathrm{~g}$ of magnesium cyanide? a. $9.7 \times 10^{23}$ b. $2.91 \times 10^{24}$ c. $2.83 \times 10^{28}$ d. $4.85 \times 10^{24}$ e. $5.65 \times 10^{27}$

          How many atoms are present in $123 \mathrm{~g}$ of magnesium cyanide?
a. $9.7 \times 10^{23}$
b. $2.91 \times 10^{24}$
c. $2.83 \times 10^{28}$
d. $4.85 \times 10^{24}$
e. $5.65 \times 10^{27}$

Added by Mireia T.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Shveta Prithiani

03/14/2022

Step 1

305 (Mg) + 2 * 12.011 (C) + 2 * 14.007 (N) Molar mass = 24.305 + 24.022 + 28.014 Molar mass = 76.341 g/mol Show more…

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How many atoms are present in $123 \mathrm{~g}$ of magnesium cyanide? a. $9.7 \times 10^{23}$ b. $2.91 \times 10^{24}$ c. $2.83 \times 10^{28}$ d. $4.85 \times 10^{24}$ e. $5.65 \times 10^{27}$