If an object moves along the y-axis (marked in feet) so that its position at time x (in seconds) is given by f(x) = 270x - 18x^2, find the following. (A) The instantaneous velocity function v = f'(x) (B) The velocity when x = 0 and x = 2 sec (C) The time(s) when v = 0 (A) v(x) = (B) The velocity when x = 0 sec is ft / sec. The velocity when x = 2 sec is ft / sec. (C) The velocity is 0 at x = sec. (Simplify your answer. Use a comma to separate answers as needed.)
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Step 1: Find the instantaneous velocity function v = f'(x) Given f(x) = 270x - 18x^2, differentiate f(x) to find v(x): f'(x) = 270 - 36x Show more…
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