If the average value of $f(x) = 3x^2 - 2ax - b$ on $[a, b]$ ($a \neq b$) \\ is $-\frac{1}{4}$, then $b = $
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To find the average value of a function on an interval, we need to evaluate the definite integral of the function over that interval and divide it by the length of the interval. The definite integral of f(x) = 3x² - 2ax - b on [a, b] is: ∫[a, b] (3x² - 2ax - b) Show more…
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