00:01
Okay, and one to answer this question, we have to talk about anti -weimer equilibrium, okay? it says that the frequency of the dominant allele, remember that first that p plus q is 1, where p is the frequency of alleleys in a population that are dominant alilis, and q is the frequency of aliases in a population that are recessive alleleys.
00:18
Also, remember that p square plus 2pq plus q is also 1, where p square is the frequency of individuals in a population that are homocybus dominant, to p q is the frequency of individuals in a population that are chytrocygose and u squared is the frequency of individuals in a population that are homozygous recessive so this question says is the frequency of the dominant allele it means the value for p is 0 .4 and the frequency for the anil recessive it means the value for q is 0 .6 okay then as you can see here p plus q is going to be 1 so practically this population is in hard the waymar equilibrium.
01:03
So it says that the dominant allele is going to code for dark hair, okay, and the small a, it means a recessive, you're going to yield light hair.
01:21
It says what is that what will be, what will that genotypic frequency of homocygous dominance, heterocygots, and homocybinis excessive in the next generation? you remember that the frequencies of adiles does not change if the population is in hard, when we're equilibrium.
01:35
So the frequency of homozygous dominant they are asking you for the value of p square and this is going to be 0 .4 square and this is going to be 0 .16...