Question

If $y = 18\sqrt{x^3} + \frac{10}{x}$ then \\ find $\frac{dy}{dx}$ \\ $\circ$ $9\sqrt{x^5} - \frac{10}{x^2}$ \\ $\circ$ $9\sqrt{x} + \frac{10}{x^2}$ \\ $\circ$ $27\sqrt{x} - \frac{10}{x^2}$ \\ $\circ$ none

          If $y = 18\sqrt{x^3} + \frac{10}{x}$ then \\
find $\frac{dy}{dx}$ \\
$\circ$ $9\sqrt{x^5} - \frac{10}{x^2}$ \\
$\circ$ $9\sqrt{x} + \frac{10}{x^2}$ \\
$\circ$ $27\sqrt{x} - \frac{10}{x^2}$ \\
$\circ$ none

If y = 18√(x^3) + (10)/(x) then

find (dy)/(dx)

∘ 9√(x^5) - (10)/(x^2)

∘ 9√(x) + (10)/(x^2)

∘ 27√(x) - (10)/(x^2)

∘ none

Added by Vincent F.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Zhumagali Shomanov

06/11/2022

Step 1

Step 1: Start with the given equation y=18\sqrt(x^(3))+(10)/(x) Show more…

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If y=18sqrt(x^(3))+(10)/(x) then find (dy)/(dx) 9sqrt(x^(5))-(10)/(x^(2)) 9sqrt(x)+(10)/(x^(2)) 27sqrt(x)-(10)/(x^(2)) none If y=18Vx3+ 10 dy find dx then 10 x2 25 10 x2 T2 none