Question

Find the steady-state expression for $v_o$ in the circuit of (Figure 1) if $i_g = 1 \cos 2000t$ A. Suppose that $v_o(t) = V_o \cos(\omega t + \phi)$, where $-180^\circ < \phi \le 180^\circ$. Determine the values $V_o$, $\omega$, $\phi$. Express your answers using three significant figures separated by commas. Express $V_o$ in volts, $\omega$ in radians per second, $\phi$ in degrees. 

          Find the steady-state expression for $v_o$ in the circuit of (Figure 1) if $i_g = 1 \cos 2000t$ A. Suppose that $v_o(t) = V_o \cos(\omega t + \phi)$, where $-180^\circ < \phi \le 180^\circ$. Determine the values $V_o$, $\omega$, $\phi$.
Express your answers using three significant figures separated by commas. Express $V_o$ in volts, $\omega$ in radians per second, $\phi$ in degrees.
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Find the steady-state expression for vo in the circuit of (Figure 1) if ig = 1 cos 2000t A. Suppose that vo(t) = Vo cos(ω t + ϕ), where -180^∘ < ϕ≤ 180^∘. Determine the values Vo, ω, ϕ. Express your answers using three significant figures separated by commas. Express Vo in volts, ω in radians per second, ϕ in degrees.

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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Part A Find the steady-state expression for i in the circuit of Figure 1 if ig = 1 cos 2000t A. Suppose that θ(t) = Vo cos(t + φ), where 180° < φ < 180°. Determine the values Vo, φ. Express your answers using three significant figures separated by commas. Express V in volts, ω in radians per second, and φ in degrees.
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Transcript

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00:09 There is 5 volt and minus 5 volt.
00:15 It is connected to b which is connecting to a earthing and also this is connecting to a which is connecting to a capacitance.
00:36 Minus 10 pf and minus j xc2 connecting and it is connecting to resistance 40k which is v0.
00:55 It is also connecting to earthing and connected to a resistance which is 100k ohm.
01:11 It is connecting to c and connecting to c to a with a resistance 20k ohm.
01:27 20k ohm and connecting to c is connecting to a capacitance which is connecting to other earthing 100 pf minus j xc2 and c is also connect to a cap resistance 5k ohm and there is a voltage v1 which is 0 degree which is vg connecting to a resistance.
02:05 So we have xc1 is equal to 1 upon omega c1 equals to 1 upon 10 power 6 multiplying by 100 multiplying by 10 power minus 12.
02:21 So it is equal to 10 power minus 4 omega 10 power 4 omega.
02:28 There is 10 power 4 omega 4 omega and xc2 is equal to 1 upon omega c2 is equal to 1 upon 10 multiplying by 6 multiplying by 10 multiplying by 10 power 12.
02:49 So it is equal to 10 power 5 omega.
02:52 So va is equal to vb equals to 0.
02:57 So this is equation number 1.
02:59 So va minus vc upon 20 multiplying by 10 power 3 plus va va minus vc upon 20 multiplying by 10 power 3 plus va minus vb vb upon 20 multiply upon minus j 10 power 5.
03:29 It is equal to 0.
03:31 So v not is equal to plus vc multiplying by j 10 power 5 upon 20 multiplying by 10 power 3.
03:44 This is equation number 2...
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