In a particular biological reaction taking place in the body at 37°C, the change in enthalpy was -125 kJmol-1 and the change in entropy was -125 kJK-1mol-1. Calculate the change in Gibbs free energy. Is the reaction spontaneous?
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Step 1: Write the relation that relates Gibbs free energy (ΔG), enthalpy change (ΔH), and entropy change (ΔS): ΔG = ΔH - TΔS Show more…
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Kartik I.
In a particular biological reaction taking place in the body at $37^{\circ} \mathrm{C}$, the change in enthalpy was $-135 \mathrm{kJ} \mathrm{mol}^{-1}$ and the change in entropy was $-136 \mathrm{J} \mathrm{K}^{-1} \mathrm{mol}^{-1}$. (a) Calculate the change in Gibbs energy. (b) Is the reaction spontaneous? (c) Calculate the total change in entropy of the system and the surroundings.
Mahendra R.
1) Calculate the value of the Gibbs Free Energy at 298 K for the conversion of A to B if the enthalpy of the reaction is -5.75 kJ·mol-1 and the change in entropy is -26.2 J·K-1·mol-1: 2)For the conversion of reactant A to product B, the change in enthalpy is 3.67 kJ·mol-1 and the change in entropy is 84.8 J·K-1·mol-1. Above what temperature, in Kelvin, does the reaction become spontaneous?
Madhur L.
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