In a particular combustion process, 144 grams of C5H12 was burned with 2 moles of O2. The combustion produced 1 mole of carbon dioxide gas. What is the percentage excess O2?
Added by Juan Jos- M.
Step 1
The balanced equation is: C5H12 + 8O2 -> 5CO2 + 6H2O From this equation, we can see that 1 mole of C5H12 requires 8 moles of O2 to completely combust. Show more…
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